Browse Articles By Category: Mathematics
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Progress Sums: 1,2,3,4,5..., -1,-2,-3,-4,-5... It can be found using the formula: Sn=(n²a₁+n)/2. Progress Sum: 1,3,6,10,15..., -1,-3,-6,-10,-15... It can be found using the formula: Sn= ((n+a₁)³-(n+a₁))/6. Progress Sum: 1,4,9,16,25..., -1,-4,-9,-16,-25... It can be found using the formula: Sn= a₁(n+a₁)(n²a₁+0.5n)/3. (Where n - is the number of summable terms, a₁ - is the first term of the progression).
Catalog: Mathematics 
3 days ago · From Andrei Verner
LONG-TERM POPULATION FORECAST AND PROSPECTS FOR CIVILIZATIONAL INTERACTION
7 days ago · From Vera Lind
MEASUREMENT SYSTEM IN ANCIENT EGYPT (ON THE QUESTION OF THE CANON OF PROPORTIONS)
24 days ago · From Vera Lind
 

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